Solve for a 4-7a=3-a+13

$4 - 7 a = 3 - a + 13$

Add $3$ and $13$ .

$4 - 7 a = - a + 16$

Move all terms containing $a$ to the left side of the equation.

Add $a$ to both sides of the equation.

$4 - 7 a + a = 16$

Add $- 7 a$ and $a$ .

$4 - 6 a = 16$

Move all terms not containing $a$ to the right side of the equation.

Subtract $4$ from both sides of the equation.

$- 6 a = 16 - 4$

Subtract $4$ from $16$ .

$- 6 a = 12$

Divide each term in $- 6 a = 12$ by $- 6$ and simplify.

Divide each term in $- 6 a = 12$ by $- 6$ .

$\frac{- 6 a}{- 6} = \frac{12}{- 6}$

Simplify the left side.

Cancel the common factor of $- 6$ .

Cancel the common factor.

$\frac{- 6 a}{- 6} = \frac{12}{- 6}$

Divide $a$ by $1$ .

$a = \frac{12}{- 6}$

Simplify the right side.

Divide $12$ by $- 6$ .

$a = - 2$