Solve for b 12b+3-3b+5=44

$12 b + 3 - 3 b + 5 = 44$

Step 1

Simplify $12 b + 3 - 3 b + 5$ .

Subtract $3 b$ from $12 b$ .

$9 b + 3 + 5 = 44$

Add $3$ and $5$ .

$9 b + 8 = 44$

Step 2

Move all terms not containing $b$ to the right side of the equation.

Subtract $8$ from both sides of the equation.

$9 b = 44 - 8$

Subtract $8$ from $44$ .

$9 b = 36$

Step 3

Divide each term in $9 b = 36$ by $9$ and simplify.

Divide each term in $9 b = 36$ by $9$ .

$\frac{9 b}{9} = \frac{36}{9}$

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{9 b}{9} = \frac{36}{9}$

Divide $b$ by $1$ .

$b = \frac{36}{9}$

Simplify the right side.

Divide $36$ by $9$ .

$b = 4$