Solve for b 2(3b-4)=8b-11

$2 (3 b - 4) = 8 b - 11$

Step 1

Simplify $2 (3 b - 4)$ .

Rewrite.

$0 + 0 + 2 (3 b - 4) = 8 b - 11$

Simplify by adding zeros.

$2 (3 b - 4) = 8 b - 11$

Apply the distributive property.

$2 (3 b) + 2 \cdot - 4 = 8 b - 11$

Multiply.

Multiply $3$ by $2$ .

$6 b + 2 \cdot - 4 = 8 b - 11$

Multiply $2$ by $- 4$ .

$6 b - 8 = 8 b - 11$

Step 2

Move all terms containing $b$ to the left side of the equation.

Subtract $8 b$ from both sides of the equation.

$6 b - 8 - 8 b = - 11$

Subtract $8 b$ from $6 b$ .

$- 2 b - 8 = - 11$

Step 3

Move all terms not containing $b$ to the right side of the equation.

Add $8$ to both sides of the equation.

$- 2 b = - 11 + 8$

Add $- 11$ and $8$ .

$- 2 b = - 3$

Step 4

Divide each term in $- 2 b = - 3$ by $- 2$ and simplify.

Divide each term in $- 2 b = - 3$ by $- 2$ .

$\frac{- 2 b}{- 2} = \frac{- 3}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 b}{- 2} = \frac{- 3}{- 2}$

Divide $b$ by $1$ .

$b = \frac{- 3}{- 2}$

Simplify the right side.

Dividing two negative values results in a positive value.

$b = \frac{3}{2}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$b = \frac{3}{2}$

Decimal Form:

$b = 1.5$

Mixed Number Form:

$b = 1 \frac{1}{2}$

Solve for b 2(3b-4)=8b-11

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