Solve for b 2(b-8)>12

$2 (b - 8) > 12$

Step 1

Divide each term in $2 (b - 8) > 12$ by $2$ and simplify.

Divide each term in $2 (b - 8) > 12$ by $2$ .

$\frac{2 (b - 8)}{2} > \frac{12}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 (b - 8)}{2} > \frac{12}{2}$

Divide $b - 8$ by $1$ .

$b - 8 > \frac{12}{2}$

Simplify the right side.

Divide $12$ by $2$ .

$b - 8 > 6$

Step 2

Move all terms not containing $b$ to the right side of the inequality.

Add $8$ to both sides of the inequality.

$b > 6 + 8$

Add $6$ and $8$ .

$b > 14$

Step 3

The result can be shown in multiple forms.

Inequality Form:

$b > 14$

Interval Notation:

$(14, \infty)$