Solve for b -4b=-5(3-b)+6

$- 4 b = - 5 (3 - b) + 6$

Step 1

Simplify $- 5 (3 - b) + 6$ .

Simplify each term.

Apply the distributive property.

$- 4 b = - 5 \cdot 3 - 5 (- b) + 6$

Multiply $- 5$ by $3$ .

$- 4 b = - 15 - 5 (- b) + 6$

Multiply $- 1$ by $- 5$ .

$- 4 b = - 15 + 5 b + 6$

Add $- 15$ and $6$ .

$- 4 b = 5 b - 9$

Step 2

Move all terms containing $b$ to the left side of the equation.

Subtract $5 b$ from both sides of the equation.

$- 4 b - 5 b = - 9$

Subtract $5 b$ from $- 4 b$ .

$- 9 b = - 9$

Step 3

Divide each term in $- 9 b = - 9$ by $- 9$ and simplify.

Divide each term in $- 9 b = - 9$ by $- 9$ .

$\frac{- 9 b}{- 9} = \frac{- 9}{- 9}$

Simplify the left side.

Cancel the common factor of $- 9$ .

Cancel the common factor.

$\frac{- 9 b}{- 9} = \frac{- 9}{- 9}$

Divide $b$ by $1$ .

$b = \frac{- 9}{- 9}$

Simplify the right side.

Divide $- 9$ by $- 9$ .

$b = 1$