Solve for b 5+5b-3=2+5b

$5 + 5 b - 3 = 2 + 5 b$

Step 1

Subtract $3$ from $5$ .

$5 b + 2 = 2 + 5 b$

Step 2

Move all terms containing $b$ to the left side of the equation.

Subtract $5 b$ from both sides of the equation.

$5 b + 2 - 5 b = 2$

Combine the opposite terms in $5 b + 2 - 5 b$ .

Subtract $5 b$ from $5 b$ .

$0 + 2 = 2$

Add $0$ and $2$ .

$2 = 2$

Step 3

Since $2 = 2$ , the equation will always be true for any value of $b$ .

All real numbers

Step 4

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$