Solve for b -8(5b-10)+5=-115

$- 8 (5 b - 10) + 5 = - 115$

Step 1

Simplify $- 8 (5 b - 10) + 5$ .

Simplify each term.

Apply the distributive property.

$- 8 (5 b) - 8 \cdot - 10 + 5 = - 115$

Multiply $5$ by $- 8$ .

$- 40 b - 8 \cdot - 10 + 5 = - 115$

Multiply $- 8$ by $- 10$ .

$- 40 b + 80 + 5 = - 115$

Add $80$ and $5$ .

$- 40 b + 85 = - 115$

Step 2

Move all terms not containing $b$ to the right side of the equation.

Subtract $85$ from both sides of the equation.

$- 40 b = - 115 - 85$

Subtract $85$ from $- 115$ .

$- 40 b = - 200$

Step 3

Divide each term in $- 40 b = - 200$ by $- 40$ and simplify.

Divide each term in $- 40 b = - 200$ by $- 40$ .

$\frac{- 40 b}{- 40} = \frac{- 200}{- 40}$

Simplify the left side.

Cancel the common factor of $- 40$ .

Cancel the common factor.

$\frac{- 40 b}{- 40} = \frac{- 200}{- 40}$

Divide $b$ by $1$ .

$b = \frac{- 200}{- 40}$

Simplify the right side.

Divide $- 200$ by $- 40$ .

$b = 5$