Solve for b -b-2>8

$- b - 2 > 8$

Step 1

Move all terms not containing $b$ to the right side of the inequality.

Add $2$ to both sides of the inequality.

$- b > 8 + 2$

Add $8$ and $2$ .

$- b > 10$

Step 2

Divide each term in $- b > 10$ by $- 1$ and simplify.

Divide each term in $- b > 10$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- b}{- 1} < \frac{10}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{b}{1} < \frac{10}{- 1}$

Divide $b$ by $1$ .

$b < \frac{10}{- 1}$

Simplify the right side.

Divide $10$ by $- 1$ .

$b < - 10$

Step 3

The result can be shown in multiple forms.

Inequality Form:

$b < - 10$

Interval Notation:

$(- \infty, - 10)$

Solve for b -b-2>8

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