Solve for b (d-8)b=g

$(d - 8) b = g$

Divide each term in $(d - 8) b = g$ by $d - 8$ .

$\frac{(d - 8) b}{d - 8} = \frac{g}{d - 8}$

Simplify the left side.

Cancel the common factor of $d - 8$ .

Cancel the common factor.

$\frac{(d - 8) b}{d - 8} = \frac{g}{d - 8}$

Divide $b$ by $1$ .

$b = \frac{g}{d - 8}$

$b = \frac{g}{d - 8}$

$b = \frac{g}{d - 8}$

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