Solve for B S=Ph+2B

$S = P h + 2 B$

Rewrite the equation as $P h + 2 B = S$ .

$P h + 2 B = S$

Subtract $P h$ from both sides of the equation.

$2 B = S - P h$

Divide each term in $2 B = S - P h$ by $2$ and simplify.

Divide each term in $2 B = S - P h$ by $2$ .

$\frac{2 B}{2} = \frac{S}{2} + \frac{- P h}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 B}{2} = \frac{S}{2} + \frac{- P h}{2}$

Divide $B$ by $1$ .

$B = \frac{S}{2} + \frac{- P h}{2}$

Simplify the right side.

Move the negative in front of the fraction.

$B = \frac{S}{2} - \frac{P h}{2}$