Solve for C 35+12C>=100

$35 + 12 C \geq 100$

Step 1

Move all terms not containing $C$ to the right side of the inequality.

Subtract $35$ from both sides of the inequality.

$12 C \geq 100 - 35$

Subtract $35$ from $100$ .

$12 C \geq 65$

Step 2

Divide each term in $12 C \geq 65$ by $12$ and simplify.

Divide each term in $12 C \geq 65$ by $12$ .

$\frac{12 C}{12} \geq \frac{65}{12}$

Simplify the left side.

Cancel the common factor of $12$ .

Cancel the common factor.

$\frac{12 C}{12} \geq \frac{65}{12}$

Divide $C$ by $1$ .

$C \geq \frac{65}{12}$

Step 3

The result can be shown in multiple forms.

Inequality Form:

$C \geq \frac{65}{12}$

Interval Notation:

$[\frac{65}{12}, \infty)$