Solve for d 7-4(d-3)=23

$7 - 4 (d - 3) = 23$

Step 1

Simplify $7 - 4 (d - 3)$ .

Simplify each term.

Apply the distributive property.

$7 - 4 d - 4 \cdot - 3 = 23$

Multiply $- 4$ by $- 3$ .

$7 - 4 d + 12 = 23$

Add $7$ and $12$ .

$- 4 d + 19 = 23$

Step 2

Move all terms not containing $d$ to the right side of the equation.

Subtract $19$ from both sides of the equation.

$- 4 d = 23 - 19$

Subtract $19$ from $23$ .

$- 4 d = 4$

Step 3

Divide each term in $- 4 d = 4$ by $- 4$ and simplify.

Divide each term in $- 4 d = 4$ by $- 4$ .

$\frac{- 4 d}{- 4} = \frac{4}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 d}{- 4} = \frac{4}{- 4}$

Divide $d$ by $1$ .

$d = \frac{4}{- 4}$

Simplify the right side.

Divide $4$ by $- 4$ .

$d = - 1$