Solve for D n=5(m^2+D)

$n = 5 (m^{2} + D)$

Rewrite the equation as $5 (m^{2} + D) = n$ .

$5 (m^{2} + D) = n$

Divide each term in $5 (m^{2} + D) = n$ by $5$ and simplify.

Divide each term in $5 (m^{2} + D) = n$ by $5$ .

$\frac{5 (m^{2} + D)}{5} = \frac{n}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 (m^{2} + D)}{5} = \frac{n}{5}$

Divide $m^{2} + D$ by $1$ .

$m^{2} + D = \frac{n}{5}$

Subtract $m^{2}$ from both sides of the equation.

$D = \frac{n}{5} - m^{2}$