Solve for f -2f+6=4-(3f-2)

$- 2 f + 6 = 4 - (3 f - 2)$

Step 1

Simplify $4 - (3 f - 2)$ .

Simplify each term.

Apply the distributive property.

$- 2 f + 6 = 4 - (3 f) - - 2$

Multiply $3$ by $- 1$ .

$- 2 f + 6 = 4 - 3 f - - 2$

Multiply $- 1$ by $- 2$ .

$- 2 f + 6 = 4 - 3 f + 2$

Add $4$ and $2$ .

$- 2 f + 6 = - 3 f + 6$

Step 2

Move all terms containing $f$ to the left side of the equation.

Add $3 f$ to both sides of the equation.

$- 2 f + 6 + 3 f = 6$

Add $- 2 f$ and $3 f$ .

$f + 6 = 6$

Step 3

Move all terms not containing $f$ to the right side of the equation.

Subtract $6$ from both sides of the equation.

$f = 6 - 6$

Subtract $6$ from $6$ .

$f = 0$