Solve for h 10-h=-4+h

$10 - h = - 4 + h$

Step 1

Move all terms containing $h$ to the left side of the equation.

Subtract $h$ from both sides of the equation.

$10 - h - h = - 4$

Subtract $h$ from $- h$ .

$10 - 2 h = - 4$

Step 2

Move all terms not containing $h$ to the right side of the equation.

Subtract $10$ from both sides of the equation.

$- 2 h = - 4 - 10$

Subtract $10$ from $- 4$ .

$- 2 h = - 14$

Step 3

Divide each term in $- 2 h = - 14$ by $- 2$ and simplify.

Divide each term in $- 2 h = - 14$ by $- 2$ .

$\frac{- 2 h}{- 2} = \frac{- 14}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 h}{- 2} = \frac{- 14}{- 2}$

Divide $h$ by $1$ .

$h = \frac{- 14}{- 2}$

Simplify the right side.

Divide $- 14$ by $- 2$ .

$h = 7$