Solve for h 7(h+3)=6(h-3)

$7 (h + 3) = 6 (h - 3)$

Step 1

Simplify $7 (h + 3)$ .

Rewrite.

$0 + 0 + 7 (h + 3) = 6 (h - 3)$

Simplify by adding zeros.

$7 (h + 3) = 6 (h - 3)$

Apply the distributive property.

$7 h + 7 \cdot 3 = 6 (h - 3)$

Multiply $7$ by $3$ .

$7 h + 21 = 6 (h - 3)$

Step 2

Simplify $6 (h - 3)$ .

Apply the distributive property.

$7 h + 21 = 6 h + 6 \cdot - 3$

Multiply $6$ by $- 3$ .

$7 h + 21 = 6 h - 18$

Step 3

Move all terms containing $h$ to the left side of the equation.

Subtract $6 h$ from both sides of the equation.

$7 h + 21 - 6 h = - 18$

Subtract $6 h$ from $7 h$ .

$h + 21 = - 18$

Step 4

Move all terms not containing $h$ to the right side of the equation.

Subtract $21$ from both sides of the equation.

$h = - 18 - 21$

Subtract $21$ from $- 18$ .

$h = - 39$