Solve for m 9+12m=6+15(m-1)

$9 + 12 m = 6 + 15 (m - 1)$

Step 1

Simplify $6 + 15 (m - 1)$ .

Simplify each term.

Apply the distributive property.

$9 + 12 m = 6 + 15 m + 15 \cdot - 1$

Multiply $15$ by $- 1$ .

$9 + 12 m = 6 + 15 m - 15$

Subtract $15$ from $6$ .

$9 + 12 m = 15 m - 9$

Step 2

Move all terms containing $m$ to the left side of the equation.

Subtract $15 m$ from both sides of the equation.

$9 + 12 m - 15 m = - 9$

Subtract $15 m$ from $12 m$ .

$9 - 3 m = - 9$

Step 3

Move all terms not containing $m$ to the right side of the equation.

Subtract $9$ from both sides of the equation.

$- 3 m = - 9 - 9$

Subtract $9$ from $- 9$ .

$- 3 m = - 18$

Step 4

Divide each term in $- 3 m = - 18$ by $- 3$ and simplify.

Divide each term in $- 3 m = - 18$ by $- 3$ .

$\frac{- 3 m}{- 3} = \frac{- 18}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 m}{- 3} = \frac{- 18}{- 3}$

Divide $m$ by $1$ .

$m = \frac{- 18}{- 3}$

Simplify the right side.

Divide $- 18$ by $- 3$ .

$m = 6$