Solve for m e^m=28

$e^{m} = 28$

Step 1

Take the natural logarithm of both sides of the equation to remove the variable from the exponent.

$\ln (e^{m}) = \ln (28)$

Step 2

Expand the left side.

Expand $\ln (e^{m})$ by moving $m$ outside the logarithm.

$m \ln (e) = \ln (28)$

The natural logarithm of $e$ is $1$ .

$m \cdot 1 = \ln (28)$

Multiply $m$ by $1$ .

$m = \ln (28)$

Step 3

The result can be shown in multiple forms.

Exact Form:

$m = \ln (28)$

Decimal Form:

$m = 3.33220451 \dots$