Solve for m m-9=(2m-12)/3

$m - 9 = \frac{2 m - 12}{3}$

Step 1

Multiply both sides by $3$ .

$(m - 9) \cdot 3 = \frac{2 m - 12}{3} \cdot 3$

Step 2

Simplify.

Simplify the left side.

Simplify $(m - 9) \cdot 3$ .

Apply the distributive property.

$m \cdot 3 - 9 \cdot 3 = \frac{2 m - 12}{3} \cdot 3$

Simplify the expression.

Move $3$ to the left of $m$ .

$3 \cdot m - 9 \cdot 3 = \frac{2 m - 12}{3} \cdot 3$

Multiply $- 9$ by $3$ .

$3 m - 27 = \frac{2 m - 12}{3} \cdot 3$

Simplify the right side.

Simplify $\frac{2 m - 12}{3} \cdot 3$ .

Factor $2$ out of $2 m - 12$ .

Factor $2$ out of $2 m$ .

$3 m - 27 = \frac{2 (m) - 12}{3} \cdot 3$

Factor $2$ out of $- 12$ .

$3 m - 27 = \frac{2 m + 2 \cdot - 6}{3} \cdot 3$

Factor $2$ out of $2 m + 2 \cdot - 6$ .

$3 m - 27 = \frac{2 (m - 6)}{3} \cdot 3$

Cancel the common factor of $3$ .

Cancel the common factor.

$3 m - 27 = \frac{2 (m - 6)}{3} \cdot 3$

Rewrite the expression.

$3 m - 27 = 2 (m - 6)$

Apply the distributive property.

$3 m - 27 = 2 m + 2 \cdot - 6$

Multiply $2$ by $- 6$ .

$3 m - 27 = 2 m - 12$

Step 3

Solve for $m$ .

Move all terms containing $m$ to the left side of the equation.

Subtract $2 m$ from both sides of the equation.

$3 m - 27 - 2 m = - 12$

Subtract $2 m$ from $3 m$ .

$m - 27 = - 12$

Move all terms not containing $m$ to the right side of the equation.

Add $27$ to both sides of the equation.

$m = - 12 + 27$

Add $- 12$ and $27$ .

$m = 15$