Solve for n 3-2(n-4)>-1

$3 - 2 (n - 4) > - 1$

Step 1

Simplify $3 - 2 (n - 4)$ .

Simplify each term.

Apply the distributive property.

$3 - 2 n - 2 \cdot - 4 > - 1$

Multiply $- 2$ by $- 4$ .

$3 - 2 n + 8 > - 1$

Add $3$ and $8$ .

$- 2 n + 11 > - 1$

Step 2

Move all terms not containing $n$ to the right side of the inequality.

Subtract $11$ from both sides of the inequality.

$- 2 n > - 1 - 11$

Subtract $11$ from $- 1$ .

$- 2 n > - 12$

Step 3

Divide each term in $- 2 n > - 12$ by $- 2$ and simplify.

Divide each term in $- 2 n > - 12$ by $- 2$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- 2 n}{- 2} < \frac{- 12}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 n}{- 2} < \frac{- 12}{- 2}$

Divide $n$ by $1$ .

$n < \frac{- 12}{- 2}$

Simplify the right side.

Divide $- 12$ by $- 2$ .

$n < 6$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$n < 6$

Interval Notation:

$(- \infty, 6)$

Solve for n 3-2(n-4)>-1

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