Solve for s (4+4s)/4=3

$\frac{4 + 4 s}{4} = 3$

Step 1

Cancel the common factor of $4 + 4 s$ and $4$ .

Factor $4$ out of $4$ .

$\frac{4 \cdot 1 + 4 s}{4} = 3$

Factor $4$ out of $4 s$ .

$\frac{4 \cdot 1 + 4 (s)}{4} = 3$

Factor $4$ out of $4 (1) + 4 (s)$ .

$\frac{4 (1 + s)}{4} = 3$

Cancel the common factors.

Factor $4$ out of $4$ .

$\frac{4 (1 + s)}{4 (1)} = 3$

Cancel the common factor.

$\frac{4 (1 + s)}{4 \cdot 1} = 3$

Rewrite the expression.

$\frac{1 + s}{1} = 3$

Divide $1 + s$ by $1$ .

$1 + s = 3$

Step 2

Move all terms not containing $s$ to the right side of the equation.

Subtract $1$ from both sides of the equation.

$s = 3 - 1$

Subtract $1$ from $3$ .

$s = 2$