Solve for s L/(p(r+s))=n

$\frac{L}{p (r + s)} = n$

Find the LCD of the terms in the equation.

Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.

$p (r + s), 1$

The LCM of one and any expression is the expression.

$p (r + s)$

Multiply each term in $\frac{L}{p (r + s)} = n$ by $p (r + s)$ to eliminate the fractions.

Multiply each term in $\frac{L}{p (r + s)} = n$ by $p (r + s)$ .

$\frac{L}{p (r + s)} (p (r + s)) = n (p (r + s))$

Simplify the left side.

Cancel the common factor of $p (r + s)$ .

Cancel the common factor.

$\frac{L}{p (r + s)} (p (r + s)) = n (p (r + s))$

Rewrite the expression.

$L = n (p (r + s))$

Simplify the right side.

Apply the distributive property.

$L = n (p r + p s)$

Apply the distributive property.

$L = n p r + n p s$

Solve the equation.

Rewrite the equation as $n p r + n p s = L$ .

$n p r + n p s = L$

Subtract $n p r$ from both sides of the equation.

$n p s = L - n p r$

Divide each term in $n p s = L - n p r$ by $n p$ and simplify.

Divide each term in $n p s = L - n p r$ by $n p$ .

$\frac{n p s}{n p} = \frac{L}{n p} + \frac{- n p r}{n p}$

Simplify the left side.

Cancel the common factor of $n$ .

Cancel the common factor.

$\frac{n p s}{n p} = \frac{L}{n p} + \frac{- n p r}{n p}$

Rewrite the expression.

$\frac{p s}{p} = \frac{L}{n p} + \frac{- n p r}{n p}$

Cancel the common factor of $p$ .

Cancel the common factor.

$\frac{p s}{p} = \frac{L}{n p} + \frac{- n p r}{n p}$

Divide $s$ by $1$ .

$s = \frac{L}{n p} + \frac{- n p r}{n p}$

Simplify the right side.

Simplify each term.

Cancel the common factor of $n$ .

Cancel the common factor.

$s = \frac{L}{n p} + \frac{- n p r}{n p}$

Rewrite the expression.

$s = \frac{L}{n p} + \frac{- 1 p r}{p}$

Cancel the common factor of $p$ .

Cancel the common factor.

$s = \frac{L}{n p} + \frac{- 1 p r}{p}$

Divide $- 1 r$ by $1$ .

$s = \frac{L}{n p} - 1 r$

Rewrite $- 1 r$ as $- r$ .

$s = \frac{L}{n p} - r$

Solve for s L/(p(r+s))=n

Related Questions

Support LCMGCF.com by disabling your adblocker.