Solve for t 4(t+1)=6t-1

$4 (t + 1) = 6 t - 1$

Step 1

Simplify $4 (t + 1)$ .

Rewrite.

$0 + 0 + 4 (t + 1) = 6 t - 1$

Simplify by adding zeros.

$4 (t + 1) = 6 t - 1$

Apply the distributive property.

$4 t + 4 \cdot 1 = 6 t - 1$

Multiply $4$ by $1$ .

$4 t + 4 = 6 t - 1$

Step 2

Move all terms containing $t$ to the left side of the equation.

Subtract $6 t$ from both sides of the equation.

$4 t + 4 - 6 t = - 1$

Subtract $6 t$ from $4 t$ .

$- 2 t + 4 = - 1$

Step 3

Move all terms not containing $t$ to the right side of the equation.

Subtract $4$ from both sides of the equation.

$- 2 t = - 1 - 4$

Subtract $4$ from $- 1$ .

$- 2 t = - 5$

Step 4

Divide each term in $- 2 t = - 5$ by $- 2$ and simplify.

Divide each term in $- 2 t = - 5$ by $- 2$ .

$\frac{- 2 t}{- 2} = \frac{- 5}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 t}{- 2} = \frac{- 5}{- 2}$

Divide $t$ by $1$ .

$t = \frac{- 5}{- 2}$

Simplify the right side.

Dividing two negative values results in a positive value.

$t = \frac{5}{2}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$t = \frac{5}{2}$

Decimal Form:

$t = 2.5$

Mixed Number Form:

$t = 2 \frac{1}{2}$