Solve for t k(t)=10t-19

$k (t) = 10 t - 19$

Step 1

Subtract $10 t$ from both sides of the equation.

$k t - 10 t = - 19$

Step 2

Factor $t$ out of $k t - 10 t$ .

Factor $t$ out of $k t$ .

$t k - 10 t = - 19$

Factor $t$ out of $- 10 t$ .

$t k + t \cdot - 10 = - 19$

Factor $t$ out of $t k + t \cdot - 10$ .

$t (k - 10) = - 19$

Step 3

Divide each term in $t (k - 10) = - 19$ by $k - 10$ and simplify.

Divide each term in $t (k - 10) = - 19$ by $k - 10$ .

$\frac{t (k - 10)}{k - 10} = \frac{- 19}{k - 10}$

Simplify the left side.

Cancel the common factor of $k - 10$ .

Cancel the common factor.

$\frac{t (k - 10)}{k - 10} = \frac{- 19}{k - 10}$

Divide $t$ by $1$ .

$t = \frac{- 19}{k - 10}$

Simplify the right side.

Move the negative in front of the fraction.

$t = - \frac{19}{k - 10}$