Solve for u 3(3u+2)+5=2(2u-2)

$3 (3 u + 2) + 5 = 2 (2 u - 2)$

Simplify $3 (3 u + 2) + 5$ .

Simplify each term.

Apply the distributive property.

$3 (3 u) + 3 \cdot 2 + 5 = 2 (2 u - 2)$

Multiply $3$ by $3$ .

$9 u + 3 \cdot 2 + 5 = 2 (2 u - 2)$

Multiply $3$ by $2$ .

$9 u + 6 + 5 = 2 (2 u - 2)$

Add $6$ and $5$ .

$9 u + 11 = 2 (2 u - 2)$

Simplify $2 (2 u - 2)$ .

Apply the distributive property.

$9 u + 11 = 2 (2 u) + 2 \cdot - 2$

Multiply.

Multiply $2$ by $2$ .

$9 u + 11 = 4 u + 2 \cdot - 2$

Multiply $2$ by $- 2$ .

$9 u + 11 = 4 u - 4$

Move all terms containing $u$ to the left side of the equation.

Subtract $4 u$ from both sides of the equation.

$9 u + 11 - 4 u = - 4$

Subtract $4 u$ from $9 u$ .

$5 u + 11 = - 4$

Move all terms not containing $u$ to the right side of the equation.

Subtract $11$ from both sides of the equation.

$5 u = - 4 - 11$

Subtract $11$ from $- 4$ .

$5 u = - 15$

Divide each term in $5 u = - 15$ by $5$ and simplify.

Divide each term in $5 u = - 15$ by $5$ .

$\frac{5 u}{5} = \frac{- 15}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 u}{5} = \frac{- 15}{5}$

Divide $u$ by $1$ .

$u = \frac{- 15}{5}$

Simplify the right side.

Divide $- 15$ by $5$ .

$u = - 3$