Solve for v 30v-25=9v^2

$30 v - 25 = 9 v^{2}$

Subtract $9 v^{2}$ from both sides of the equation.

$30 v - 25 - 9 v^{2} = 0$

Factor the left side of the equation.

Factor $- 1$ out of $30 v - 25 - 9 v^{2}$ .

Reorder the expression.

Move $- 25$ .

$30 v - 9 v^{2} - 25 = 0$

Reorder $30 v$ and $- 9 v^{2}$ .

$- 9 v^{2} + 30 v - 25 = 0$

Factor $- 1$ out of $- 9 v^{2}$ .

$- (9 v^{2}) + 30 v - 25 = 0$

Factor $- 1$ out of $30 v$ .

$- (9 v^{2}) - (- 30 v) - 25 = 0$

Rewrite $- 25$ as $- 1 (25)$ .

$- (9 v^{2}) - (- 30 v) - 1 \cdot 25 = 0$

Factor $- 1$ out of $- (9 v^{2}) - (- 30 v)$ .

$- (9 v^{2} - 30 v) - 1 \cdot 25 = 0$

Factor $- 1$ out of $- (9 v^{2} - 30 v) - 1 (25)$ .

$- (9 v^{2} - 30 v + 25) = 0$

Factor using the perfect square rule.

Rewrite $9 v^{2}$ as ${(3 v)}^{2}$ .

$- ({(3 v)}^{2} - 30 v + 25) = 0$

Rewrite $25$ as $5^{2}$ .

$- ({(3 v)}^{2} - 30 v + 5^{2}) = 0$

Check that the middle term is two times the product of the numbers being squared in the first term and third term.

$30 v = 2 \cdot (3 v) \cdot 5$

Rewrite the polynomial.

$- ({(3 v)}^{2} - 2 \cdot (3 v) \cdot 5 + 5^{2}) = 0$

Factor using the perfect square trinomial rule $a^{2} - 2 a b + b^{2} = {(a - b)}^{2}$ , where $a = 3 v$ and $b = 5$ .

$- {(3 v - 5)}^{2} = 0$

Divide each term in $- {(3 v - 5)}^{2} = 0$ by $- 1$ and simplify.

Divide each term in $- {(3 v - 5)}^{2} = 0$ by $- 1$ .

$\frac{- {(3 v - 5)}^{2}}{- 1} = \frac{0}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{{(3 v - 5)}^{2}}{1} = \frac{0}{- 1}$

Divide ${(3 v - 5)}^{2}$ by $1$ .

${(3 v - 5)}^{2} = \frac{0}{- 1}$

Simplify the right side.

Divide $0$ by $- 1$ .

${(3 v - 5)}^{2} = 0$

Set the $3 v - 5$ equal to $0$ .

$3 v - 5 = 0$

Solve for $v$ .

Add $5$ to both sides of the equation.

$3 v = 5$

Divide each term in $3 v = 5$ by $3$ and simplify.

Divide each term in $3 v = 5$ by $3$ .

$\frac{3 v}{3} = \frac{5}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 v}{3} = \frac{5}{3}$

Divide $v$ by $1$ .

$v = \frac{5}{3}$

The result can be shown in multiple forms.

Exact Form:

$v = \frac{5}{3}$

Decimal Form:

$v = 1.\overline{6}$

Mixed Number Form:

$v = 1 \frac{2}{3}$

Solve for v 30v-25=9v^2

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