Solve for w 3w-5>2w+w-7

$3 w - 5 > 2 w + w - 7$

Rewrite so $w$ is on the left side of the inequality.

$2 w + w - 7 < 3 w - 5$

Add $2 w$ and $w$ .

$3 w - 7 < 3 w - 5$

Move all terms containing $w$ to the left side of the inequality.

Subtract $3 w$ from both sides of the inequality.

$3 w - 7 - 3 w < - 5$

Combine the opposite terms in $3 w - 7 - 3 w$ .

Subtract $3 w$ from $3 w$ .

$0 - 7 < - 5$

Subtract $7$ from $0$ .

$- 7 < - 5$

Since $- 7 < - 5$ , the inequality will always be true for any value of $w$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$