Solve for x 2-3/8=(2x+5)/24

$2 - \frac{3}{8} = \frac{2 x + 5}{24}$

Step 1

Rewrite the equation as $\frac{2 x + 5}{24} = 2 - \frac{3}{8}$ .

$\frac{2 x + 5}{24} = 2 - \frac{3}{8}$

Step 2

Multiply both sides by $24$ .

$\frac{2 x + 5}{24} \cdot 24 = (2 - \frac{3}{8}) \cdot 24$

Step 3

Simplify.

Simplify the left side.

Cancel the common factor of $24$ .

Cancel the common factor.

$\frac{2 x + 5}{24} \cdot 24 = (2 - \frac{3}{8}) \cdot 24$

Rewrite the expression.

$2 x + 5 = (2 - \frac{3}{8}) \cdot 24$

Simplify the right side.

Simplify $(2 - \frac{3}{8}) \cdot 24$ .

To write $2$ as a fraction with a common denominator, multiply by $\frac{8}{8}$ .

$2 x + 5 = (2 \cdot \frac{8}{8} - \frac{3}{8}) \cdot 24$

Combine $2$ and $\frac{8}{8}$ .

$2 x + 5 = (\frac{2 \cdot 8}{8} - \frac{3}{8}) \cdot 24$

Combine the numerators over the common denominator.

$2 x + 5 = \frac{2 \cdot 8 - 3}{8} \cdot 24$

Simplify the numerator.

Multiply $2$ by $8$ .

$2 x + 5 = \frac{16 - 3}{8} \cdot 24$

Subtract $3$ from $16$ .

$2 x + 5 = \frac{13}{8} \cdot 24$

Cancel the common factor of $8$ .

Factor $8$ out of $24$ .

$2 x + 5 = \frac{13}{8} \cdot (8 (3))$

Cancel the common factor.

$2 x + 5 = \frac{13}{8} \cdot (8 \cdot 3)$

Rewrite the expression.

$2 x + 5 = 13 \cdot 3$

Multiply $13$ by $3$ .

$2 x + 5 = 39$

Step 4

Solve for $x$ .

Move all terms not containing $x$ to the right side of the equation.

Subtract $5$ from both sides of the equation.

$2 x = 39 - 5$

Subtract $5$ from $39$ .

$2 x = 34$

Divide each term in $2 x = 34$ by $2$ and simplify.

Divide each term in $2 x = 34$ by $2$ .

$\frac{2 x}{2} = \frac{34}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{34}{2}$

Divide $x$ by $1$ .

$x = \frac{34}{2}$

Simplify the right side.

Divide $34$ by $2$ .

$x = 17$

Solve for x 2-3/8=(2x+5)/24

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