Solve for x 2(3+x)=5x+54

$2 (3 + x) = 5 x + 54$

Step 1

Simplify $2 (3 + x)$ .

Rewrite.

$0 + 0 + 2 (3 + x) = 5 x + 54$

Simplify by adding zeros.

$2 (3 + x) = 5 x + 54$

Apply the distributive property.

$2 \cdot 3 + 2 x = 5 x + 54$

Multiply $2$ by $3$ .

$6 + 2 x = 5 x + 54$

Step 2

Move all terms containing $x$ to the left side of the equation.

Subtract $5 x$ from both sides of the equation.

$6 + 2 x - 5 x = 54$

Subtract $5 x$ from $2 x$ .

$6 - 3 x = 54$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Subtract $6$ from both sides of the equation.

$- 3 x = 54 - 6$

Subtract $6$ from $54$ .

$- 3 x = 48$

Step 4

Divide each term in $- 3 x = 48$ by $- 3$ and simplify.

Divide each term in $- 3 x = 48$ by $- 3$ .

$\frac{- 3 x}{- 3} = \frac{48}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 x}{- 3} = \frac{48}{- 3}$

Divide $x$ by $1$ .

$x = \frac{48}{- 3}$

Simplify the right side.

Divide $48$ by $- 3$ .

$x = - 16$