Solve for x 2(4x-3)-8=4+2x

$2 (4 x - 3) - 8 = 4 + 2 x$

Step 1

Simplify $2 (4 x - 3) - 8$ .

Simplify each term.

Apply the distributive property.

$2 (4 x) + 2 \cdot - 3 - 8 = 4 + 2 x$

Multiply $4$ by $2$ .

$8 x + 2 \cdot - 3 - 8 = 4 + 2 x$

Multiply $2$ by $- 3$ .

$8 x - 6 - 8 = 4 + 2 x$

Subtract $8$ from $- 6$ .

$8 x - 14 = 4 + 2 x$

Step 2

Move all terms containing $x$ to the left side of the equation.

Subtract $2 x$ from both sides of the equation.

$8 x - 14 - 2 x = 4$

Subtract $2 x$ from $8 x$ .

$6 x - 14 = 4$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Add $14$ to both sides of the equation.

$6 x = 4 + 14$

Add $4$ and $14$ .

$6 x = 18$

Step 4

Divide each term in $6 x = 18$ by $6$ and simplify.

Divide each term in $6 x = 18$ by $6$ .

$\frac{6 x}{6} = \frac{18}{6}$

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 x}{6} = \frac{18}{6}$

Divide $x$ by $1$ .

$x = \frac{18}{6}$

Simplify the right side.

Divide $18$ by $6$ .

$x = 3$