Solve for x 2 square root of x-8<24

$2 \sqrt{x - 8} < 24$

To remove the radical on the left side of the inequality, square both sides of the inequality.

${(2 \sqrt{x - 8})}^{2} < 24^{2}$

Simplify each side of the inequality.

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{x - 8}$ as ${(x - 8)}^{\frac{1}{2}}$ .

${(2 {(x - 8)}^{\frac{1}{2}})}^{2} < 24^{2}$

Simplify the left side.

Simplify ${(2 {(x - 8)}^{\frac{1}{2}})}^{2}$ .

Apply the product rule to $2 {(x - 8)}^{\frac{1}{2}}$ .

$2^{2} {({(x - 8)}^{\frac{1}{2}})}^{2} < 24^{2}$

Raise $2$ to the power of $2$ .

$4 {({(x - 8)}^{\frac{1}{2}})}^{2} < 24^{2}$

Multiply the exponents in ${({(x - 8)}^{\frac{1}{2}})}^{2}$ .

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$4 {(x - 8)}^{\frac{1}{2} \cdot 2} < 24^{2}$

Cancel the common factor of $2$ .

Cancel the common factor.

$4 {(x - 8)}^{\frac{1}{2} \cdot 2} < 24^{2}$

Rewrite the expression.

$4 {(x - 8)}^{1} < 24^{2}$

Simplify.

$4 (x - 8) < 24^{2}$

Apply the distributive property.

$4 x + 4 \cdot - 8 < 24^{2}$

Multiply $4$ by $- 8$ .

$4 x - 32 < 24^{2}$

Simplify the right side.

Raise $24$ to the power of $2$ .

$4 x - 32 < 576$

Solve for $x$ .

Move all terms not containing $x$ to the right side of the inequality.

Add $32$ to both sides of the inequality.

$4 x < 576 + 32$

Add $576$ and $32$ .

$4 x < 608$

Divide each term in $4 x < 608$ by $4$ and simplify.

Divide each term in $4 x < 608$ by $4$ .

$\frac{4 x}{4} < \frac{608}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 x}{4} < \frac{608}{4}$

Divide $x$ by $1$ .

$x < \frac{608}{4}$

Simplify the right side.

Divide $608$ by $4$ .

$x < 152$

Find the domain of $2 \sqrt{x - 8} - 24$ .

Set the radicand in $\sqrt{x - 8}$ greater than or equal to $0$ to find where the expression is defined.

$x - 8 \geq 0$

Add $8$ to both sides of the inequality.

$x \geq 8$

The domain is all values of $x$ that make the expression defined.

$[8, \infty)$

Use each root to create test intervals.

$x < 8$

$8 < x < 152$

$x > 152$

Choose a test value from each interval and plug this value into the original inequality to determine which intervals satisfy the inequality.

Test a value on the interval $x < 8$ to see if it makes the inequality true.

Choose a value on the interval $x < 8$ and see if this value makes the original inequality true.

$x = 0$

Replace $x$ with $0$ in the original inequality.

$2 \sqrt{(0) - 8} < 24$

The left side is not equal to the right side, which means that the given statement is false.

False

Test a value on the interval $8 < x < 152$ to see if it makes the inequality true.

Choose a value on the interval $8 < x < 152$ and see if this value makes the original inequality true.

$x = 10$

Replace $x$ with $10$ in the original inequality.

$2 \sqrt{(10) - 8} < 24$

The left side $2.82842712$ is less than the right side $24$ , which means that the given statement is always true.

True

Test a value on the interval $x > 152$ to see if it makes the inequality true.

Choose a value on the interval $x > 152$ and see if this value makes the original inequality true.

$x = 154$

Replace $x$ with $154$ in the original inequality.

$2 \sqrt{(154) - 8} < 24$

The left side $24.16609194$ is not less than the right side $24$ , which means that the given statement is false.

False

Compare the intervals to determine which ones satisfy the original inequality.

$x < 8$ False

$8 < x < 152$ True

$x > 152$ False

$x < 8$ False

$8 < x < 152$ True

$x > 152$ False

The solution consists of all of the true intervals.

$8 < x < 152$

The result can be shown in multiple forms.

Inequality Form:

$8 < x < 152$

Interval Notation:

$(8, 152)$

Solve for x 2 square root of x-8<24

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