Solve for x 3-4x=18+x

$3 - 4 x = 18 + x$

Step 1

Move all terms containing $x$ to the left side of the equation.

Subtract $x$ from both sides of the equation.

$3 - 4 x - x = 18$

Subtract $x$ from $- 4 x$ .

$3 - 5 x = 18$

Step 2

Move all terms not containing $x$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$- 5 x = 18 - 3$

Subtract $3$ from $18$ .

$- 5 x = 15$

Step 3

Divide each term in $- 5 x = 15$ by $- 5$ and simplify.

Divide each term in $- 5 x = 15$ by $- 5$ .

$\frac{- 5 x}{- 5} = \frac{15}{- 5}$

Simplify the left side.

Cancel the common factor of $- 5$ .

Cancel the common factor.

$\frac{- 5 x}{- 5} = \frac{15}{- 5}$

Divide $x$ by $1$ .

$x = \frac{15}{- 5}$

Simplify the right side.

Divide $15$ by $- 5$ .

$x = - 3$