Solve for x 3-5x=-9+x

$3 - 5 x = - 9 + x$

Step 1

Move all terms containing $x$ to the left side of the equation.

Subtract $x$ from both sides of the equation.

$3 - 5 x - x = - 9$

Subtract $x$ from $- 5 x$ .

$3 - 6 x = - 9$

Step 2

Move all terms not containing $x$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$- 6 x = - 9 - 3$

Subtract $3$ from $- 9$ .

$- 6 x = - 12$

Step 3

Divide each term in $- 6 x = - 12$ by $- 6$ and simplify.

Divide each term in $- 6 x = - 12$ by $- 6$ .

$\frac{- 6 x}{- 6} = \frac{- 12}{- 6}$

Simplify the left side.

Cancel the common factor of $- 6$ .

Cancel the common factor.

$\frac{- 6 x}{- 6} = \frac{- 12}{- 6}$

Divide $x$ by $1$ .

$x = \frac{- 12}{- 6}$

Simplify the right side.

Divide $- 12$ by $- 6$ .

$x = 2$