Solve for x 3-x>=0

$3 - x \geq 0$

Subtract $3$ from both sides of the inequality.

$- x \geq - 3$

Divide each term in $- x \geq - 3$ by $- 1$ and simplify.

Divide each term in $- x \geq - 3$ by $- 1$ . When multiplying or dividing both sides of an inequality by a negative value, flip the direction of the inequality sign.

$\frac{- x}{- 1} \leq \frac{- 3}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} \leq \frac{- 3}{- 1}$

Divide $x$ by $1$ .

$x \leq \frac{- 3}{- 1}$

Simplify the right side.

Divide $- 3$ by $- 1$ .

$x \leq 3$

The result can be shown in multiple forms.

Inequality Form:

$x \leq 3$

Interval Notation:

$(- \infty, 3]$

Solve for x 3-x>=0

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