Solve for x 3(x+2)=y-6

$3 (x + 2) = y - 6$

Step 1

Divide each term in $3 (x + 2) = y - 6$ by $3$ and simplify.

Divide each term in $3 (x + 2) = y - 6$ by $3$ .

$\frac{3 (x + 2)}{3} = \frac{y}{3} + \frac{- 6}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 (x + 2)}{3} = \frac{y}{3} + \frac{- 6}{3}$

Divide $x + 2$ by $1$ .

$x + 2 = \frac{y}{3} + \frac{- 6}{3}$

Simplify the right side.

Divide $- 6$ by $3$ .

$x + 2 = \frac{y}{3} - 2$

Step 2

Move all terms not containing $x$ to the right side of the equation.

Subtract $2$ from both sides of the equation.

$x = \frac{y}{3} - 2 - 2$

Subtract $2$ from $- 2$ .

$x = \frac{y}{3} - 4$