Solve for x 3(x-4)-4(x-3)=x+3-(x-2)

$3 (x - 4) - 4 (x - 3) = x + 3 - (x - 2)$

Step 1

Simplify $3 (x - 4) - 4 (x - 3)$ .

Rewrite.

$3 (x - 4) - 4 (x - 3) - x + x = x + 3 - (x - 2)$

Simplify by adding terms.

$3 (x - 4) - 4 (x - 3) = x + 3 - (x - 2)$

Simplify each term.

Apply the distributive property.

$3 x + 3 \cdot - 4 - 4 (x - 3) = x + 3 - (x - 2)$

Multiply $3$ by $- 4$ .

$3 x - 12 - 4 (x - 3) = x + 3 - (x - 2)$

Apply the distributive property.

$3 x - 12 - 4 x - 4 \cdot - 3 = x + 3 - (x - 2)$

Multiply $- 4$ by $- 3$ .

$3 x - 12 - 4 x + 12 = x + 3 - (x - 2)$

Simplify by adding terms.

Combine the opposite terms in $3 x - 12 - 4 x + 12$ .

Add $- 12$ and $12$ .

$3 x - 4 x + 0 = x + 3 - (x - 2)$

Add $3 x - 4 x$ and $0$ .

$3 x - 4 x = x + 3 - (x - 2)$

Subtract $4 x$ from $3 x$ .

$- x = x + 3 - (x - 2)$

Step 2

Simplify $x + 3 - (x - 2)$ .

Simplify each term.

Apply the distributive property.

$- x = x + 3 - x - - 2$

Multiply $- 1$ by $- 2$ .

$- x = x + 3 - x + 2$

Simplify by adding terms.

Combine the opposite terms in $x + 3 - x + 2$ .

Subtract $x$ from $x$ .

$- x = 0 + 3 + 2$

Add $0$ and $3$ .

$- x = 3 + 2$

Add $3$ and $2$ .

$- x = 5$

Step 3

Divide each term in $- x = 5$ by $- 1$ and simplify.

Divide each term in $- x = 5$ by $- 1$ .

$\frac{- x}{- 1} = \frac{5}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{5}{- 1}$

Divide $x$ by $1$ .

$x = \frac{5}{- 1}$

Simplify the right side.

Divide $5$ by $- 1$ .

$x = - 5$

Solve for x 3(x-4)-4(x-3)=x+3-(x-2)

Related Questions

Support LCMGCF.com by disabling your adblocker.