Solve for x 3x+2(x-8)>x

$3 x + 2 (x - 8) > x$

Simplify $3 x + 2 (x - 8)$ .

Simplify each term.

Apply the distributive property.

$3 x + 2 x + 2 \cdot - 8 > x$

Multiply $2$ by $- 8$ .

$3 x + 2 x - 16 > x$

Add $3 x$ and $2 x$ .

$5 x - 16 > x$

Move all terms containing $x$ to the left side of the inequality.

Subtract $x$ from both sides of the inequality.

$5 x - 16 - x > 0$

Subtract $x$ from $5 x$ .

$4 x - 16 > 0$

Add $16$ to both sides of the inequality.

$4 x > 16$

Divide each term in $4 x > 16$ by $4$ and simplify.

Divide each term in $4 x > 16$ by $4$ .

$\frac{4 x}{4} > \frac{16}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 x}{4} > \frac{16}{4}$

Divide $x$ by $1$ .

$x > \frac{16}{4}$

Simplify the right side.

Divide $16$ by $4$ .

$x > 4$

The result can be shown in multiple forms.

Inequality Form:

$x > 4$

Interval Notation:

$(4, \infty)$