Solve for x 3x+4-x=5x-10-x

$3 x + 4 - x = 5 x - 10 - x$

Subtract $x$ from $3 x$ .

$2 x + 4 = 5 x - 10 - x$

Subtract $x$ from $5 x$ .

$2 x + 4 = 4 x - 10$

Move all terms containing $x$ to the left side of the equation.

Subtract $4 x$ from both sides of the equation.

$2 x + 4 - 4 x = - 10$

Subtract $4 x$ from $2 x$ .

$- 2 x + 4 = - 10$

Move all terms not containing $x$ to the right side of the equation.

Subtract $4$ from both sides of the equation.

$- 2 x = - 10 - 4$

Subtract $4$ from $- 10$ .

$- 2 x = - 14$

Divide each term in $- 2 x = - 14$ by $- 2$ and simplify.

Divide each term in $- 2 x = - 14$ by $- 2$ .

$\frac{- 2 x}{- 2} = \frac{- 14}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 x}{- 2} = \frac{- 14}{- 2}$

Divide $x$ by $1$ .

$x = \frac{- 14}{- 2}$

Simplify the right side.

Divide $- 14$ by $- 2$ .

$x = 7$