Solve for x (3x)/7+2/7=2

$\frac{3 x}{7} + \frac{2}{7} = 2$

Step 1

Move all terms not containing $x$ to the right side of the equation.

Subtract $\frac{2}{7}$ from both sides of the equation.

$\frac{3 x}{7} = 2 - \frac{2}{7}$

To write $2$ as a fraction with a common denominator, multiply by $\frac{7}{7}$ .

$\frac{3 x}{7} = 2 \cdot \frac{7}{7} - \frac{2}{7}$

Combine $2$ and $\frac{7}{7}$ .

$\frac{3 x}{7} = \frac{2 \cdot 7}{7} - \frac{2}{7}$

Combine the numerators over the common denominator.

$\frac{3 x}{7} = \frac{2 \cdot 7 - 2}{7}$

Simplify the numerator.

Multiply $2$ by $7$ .

$\frac{3 x}{7} = \frac{14 - 2}{7}$

Subtract $2$ from $14$ .

$\frac{3 x}{7} = \frac{12}{7}$

Step 2

Since the expression on each side of the equation has the same denominator, the numerators must be equal.

$3 x = 12$

Step 3

Divide each term in $3 x = 12$ by $3$ and simplify.

Divide each term in $3 x = 12$ by $3$ .

$\frac{3 x}{3} = \frac{12}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 x}{3} = \frac{12}{3}$

Divide $x$ by $1$ .

$x = \frac{12}{3}$

Simplify the right side.

Divide $12$ by $3$ .

$x = 4$