Solve for x -4(2x-5)-(7-3x)=4(x+3)

$- 4 (2 x - 5) - (7 - 3 x) = 4 (x + 3)$

Step 1

Simplify $- 4 (2 x - 5) - (7 - 3 x)$ .

Simplify each term.

Apply the distributive property.

$- 4 (2 x) - 4 \cdot - 5 - (7 - 3 x) = 4 (x + 3)$

Multiply $2$ by $- 4$ .

$- 8 x - 4 \cdot - 5 - (7 - 3 x) = 4 (x + 3)$

Multiply $- 4$ by $- 5$ .

$- 8 x + 20 - (7 - 3 x) = 4 (x + 3)$

Apply the distributive property.

$- 8 x + 20 - 1 \cdot 7 - (- 3 x) = 4 (x + 3)$

Multiply $- 1$ by $7$ .

$- 8 x + 20 - 7 - (- 3 x) = 4 (x + 3)$

Multiply $- 3$ by $- 1$ .

$- 8 x + 20 - 7 + 3 x = 4 (x + 3)$

Simplify by adding terms.

Add $- 8 x$ and $3 x$ .

$- 5 x + 20 - 7 = 4 (x + 3)$

Subtract $7$ from $20$ .

$- 5 x + 13 = 4 (x + 3)$

Step 2

Simplify $4 (x + 3)$ .

Apply the distributive property.

$- 5 x + 13 = 4 x + 4 \cdot 3$

Multiply $4$ by $3$ .

$- 5 x + 13 = 4 x + 12$

Step 3

Move all terms containing $x$ to the left side of the equation.

Subtract $4 x$ from both sides of the equation.

$- 5 x + 13 - 4 x = 12$

Subtract $4 x$ from $- 5 x$ .

$- 9 x + 13 = 12$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Subtract $13$ from both sides of the equation.

$- 9 x = 12 - 13$

Subtract $13$ from $12$ .

$- 9 x = - 1$

Step 5

Divide each term in $- 9 x = - 1$ by $- 9$ and simplify.

Divide each term in $- 9 x = - 1$ by $- 9$ .

$\frac{- 9 x}{- 9} = \frac{- 1}{- 9}$

Simplify the left side.

Cancel the common factor of $- 9$ .

Cancel the common factor.

$\frac{- 9 x}{- 9} = \frac{- 1}{- 9}$

Divide $x$ by $1$ .

$x = \frac{- 1}{- 9}$

Simplify the right side.

Dividing two negative values results in a positive value.

$x = \frac{1}{9}$

Step 6

The result can be shown in multiple forms.

Exact Form:

$x = \frac{1}{9}$

Decimal Form:

$x = 0.\overline{1}$

Solve for x -4(2x-5)-(7-3x)=4(x+3)

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