Solve for x 4x+2(3x-9)=x

$4 x + 2 (3 x - 9) = x$

Step 1

Simplify $4 x + 2 (3 x - 9)$ .

Simplify each term.

Apply the distributive property.

$4 x + 2 (3 x) + 2 \cdot - 9 = x$

Multiply $3$ by $2$ .

$4 x + 6 x + 2 \cdot - 9 = x$

Multiply $2$ by $- 9$ .

$4 x + 6 x - 18 = x$

Add $4 x$ and $6 x$ .

$10 x - 18 = x$

Step 2

Move all terms containing $x$ to the left side of the equation.

Subtract $x$ from both sides of the equation.

$10 x - 18 - x = 0$

Subtract $x$ from $10 x$ .

$9 x - 18 = 0$

Step 3

Add $18$ to both sides of the equation.

$9 x = 18$

Step 4

Divide each term in $9 x = 18$ by $9$ and simplify.

Divide each term in $9 x = 18$ by $9$ .

$\frac{9 x}{9} = \frac{18}{9}$

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{9 x}{9} = \frac{18}{9}$

Divide $x$ by $1$ .

$x = \frac{18}{9}$

Simplify the right side.

Divide $18$ by $9$ .

$x = 2$