Solve for x 4x^3=16

$4 x^{3} = 16$

Subtract $16$ from both sides of the equation.

$4 x^{3} - 16 = 0$

Factor $4$ out of $4 x^{3} - 16$ .

Factor $4$ out of $4 x^{3}$ .

$4 (x^{3}) - 16 = 0$

Factor $4$ out of $- 16$ .

$4 x^{3} + 4 \cdot - 4 = 0$

Factor $4$ out of $4 x^{3} + 4 \cdot - 4$ .

$4 (x^{3} - 4) = 0$

Divide each term in $4 (x^{3} - 4) = 0$ by $4$ and simplify.

Divide each term in $4 (x^{3} - 4) = 0$ by $4$ .

$\frac{4 (x^{3} - 4)}{4} = \frac{0}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 (x^{3} - 4)}{4} = \frac{0}{4}$

Divide $x^{3} - 4$ by $1$ .

$x^{3} - 4 = \frac{0}{4}$

Simplify the right side.

Divide $0$ by $4$ .

$x^{3} - 4 = 0$

Add $4$ to both sides of the equation.

$x^{3} = 4$

Take the cube root of both sides of the equation to eliminate the exponent on the left side.

$x = \sqrt[3]{4}$

The result can be shown in multiple forms.

Exact Form:

$x = \sqrt[3]{4}$

Decimal Form:

$x = 1.58740105 \dots$