Solve for x 5-2(x-7)=x+1+3x

$5 - 2 (x - 7) = x + 1 + 3 x$

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$x + 1 + 3 x = 5 - 2 (x - 7)$

Add $x$ and $3 x$ .

$4 x + 1 = 5 - 2 (x - 7)$

Simplify $5 - 2 (x - 7)$ .

Simplify each term.

Apply the distributive property.

$4 x + 1 = 5 - 2 x - 2 \cdot - 7$

Multiply $- 2$ by $- 7$ .

$4 x + 1 = 5 - 2 x + 14$

Add $5$ and $14$ .

$4 x + 1 = - 2 x + 19$

Move all terms containing $x$ to the left side of the equation.

Add $2 x$ to both sides of the equation.

$4 x + 1 + 2 x = 19$

Add $4 x$ and $2 x$ .

$6 x + 1 = 19$

Move all terms not containing $x$ to the right side of the equation.

Subtract $1$ from both sides of the equation.

$6 x = 19 - 1$

Subtract $1$ from $19$ .

$6 x = 18$

Divide each term in $6 x = 18$ by $6$ and simplify.

Divide each term in $6 x = 18$ by $6$ .

$\frac{6 x}{6} = \frac{18}{6}$

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 x}{6} = \frac{18}{6}$

Divide $x$ by $1$ .

$x = \frac{18}{6}$

Simplify the right side.

Divide $18$ by $6$ .

$x = 3$