Solve for x 8x-2(x+1)=2(3x-1)

$8 x - 2 (x + 1) = 2 (3 x - 1)$

Simplify $8 x - 2 (x + 1)$ .

Simplify each term.

Apply the distributive property.

$8 x - 2 x - 2 \cdot 1 = 2 (3 x - 1)$

Multiply $- 2$ by $1$ .

$8 x - 2 x - 2 = 2 (3 x - 1)$

Subtract $2 x$ from $8 x$ .

$6 x - 2 = 2 (3 x - 1)$

Simplify $2 (3 x - 1)$ .

Apply the distributive property.

$6 x - 2 = 2 (3 x) + 2 \cdot - 1$

Multiply.

Multiply $3$ by $2$ .

$6 x - 2 = 6 x + 2 \cdot - 1$

Multiply $2$ by $- 1$ .

$6 x - 2 = 6 x - 2$

Move all terms containing $x$ to the left side of the equation.

Subtract $6 x$ from both sides of the equation.

$6 x - 2 - 6 x = - 2$

Combine the opposite terms in $6 x - 2 - 6 x$ .

Subtract $6 x$ from $6 x$ .

$0 - 2 = - 2$

Subtract $2$ from $0$ .

$- 2 = - 2$

Since $- 2 = - 2$ , the equation will always be true for any value of $x$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$