Solve for x 5^(x^2)=25^x

$5^{x^{2}} = 25^{x}$

Step 1

Create equivalent expressions in the equation that all have equal bases.

$5^{x^{2}} = 5^{2 x}$

Step 2

Since the bases are the same, then two expressions are only equal if the exponents are also equal.

$x^{2} = 2 x$

Step 3

Solve for $x$ .

Subtract $2 x$ from both sides of the equation.

$x^{2} - 2 x = 0$

Factor $x$ out of $x^{2} - 2 x$ .

Factor $x$ out of $x^{2}$ .

$x \cdot x - 2 x = 0$

Factor $x$ out of $- 2 x$ .

$x \cdot x + x \cdot - 2 = 0$

Factor $x$ out of $x \cdot x + x \cdot - 2$ .

$x (x - 2) = 0$

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x = 0$

$x - 2 = 0$

Set $x$ equal to $0$ .

$x = 0$

Set $x - 2$ equal to $0$ and solve for $x$ .

Set $x - 2$ equal to $0$ .

$x - 2 = 0$

Add $2$ to both sides of the equation.

$x = 2$

The final solution is all the values that make $x (x - 2) = 0$ true.

$x = 0, 2$