Solve for x 6x-4/7(21x-35)=2

$6 x - \frac{4}{7} (21 x - 35) = 2$

Step 1

Simplify $6 x - \frac{4}{7} \cdot (21 x - 35)$ .

Simplify each term.

Apply the distributive property.

$6 x - \frac{4}{7} (21 x) - \frac{4}{7} \cdot - 35 = 2$

Cancel the common factor of $7$ .

Move the leading negative in $- \frac{4}{7}$ into the numerator.

$6 x + \frac{- 4}{7} (21 x) - \frac{4}{7} \cdot - 35 = 2$

Factor $7$ out of $21 x$ .

$6 x + \frac{- 4}{7} (7 (3 x)) - \frac{4}{7} \cdot - 35 = 2$

Cancel the common factor.

$6 x + \frac{- 4}{7} (7 (3 x)) - \frac{4}{7} \cdot - 35 = 2$

Rewrite the expression.

$6 x - 4 (3 x) - \frac{4}{7} \cdot - 35 = 2$

Multiply $3$ by $- 4$ .

$6 x - 12 x - \frac{4}{7} \cdot - 35 = 2$

Cancel the common factor of $7$ .

Move the leading negative in $- \frac{4}{7}$ into the numerator.

$6 x - 12 x + \frac{- 4}{7} \cdot - 35 = 2$

Factor $7$ out of $- 35$ .

$6 x - 12 x + \frac{- 4}{7} \cdot (7 (- 5)) = 2$

Cancel the common factor.

$6 x - 12 x + \frac{- 4}{7} \cdot (7 \cdot - 5) = 2$

Rewrite the expression.

$6 x - 12 x - 4 \cdot - 5 = 2$

Multiply $- 4$ by $- 5$ .

$6 x - 12 x + 20 = 2$

Subtract $12 x$ from $6 x$ .

$- 6 x + 20 = 2$

Step 2

Move all terms not containing $x$ to the right side of the equation.

Subtract $20$ from both sides of the equation.

$- 6 x = 2 - 20$

Subtract $20$ from $2$ .

$- 6 x = - 18$

Step 3

Divide each term in $- 6 x = - 18$ by $- 6$ and simplify.

Divide each term in $- 6 x = - 18$ by $- 6$ .

$\frac{- 6 x}{- 6} = \frac{- 18}{- 6}$

Simplify the left side.

Cancel the common factor of $- 6$ .

Cancel the common factor.

$\frac{- 6 x}{- 6} = \frac{- 18}{- 6}$

Divide $x$ by $1$ .

$x = \frac{- 18}{- 6}$

Simplify the right side.

Divide $- 18$ by $- 6$ .

$x = 3$

Solve for x 6x-4/7(21x-35)=2

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