Solve for x 75=-5(-3-4x)

$75 = - 5 (- 3 - 4 x)$

Rewrite the equation as $- 5 (- 3 - 4 x) = 75$ .

$- 5 (- 3 - 4 x) = 75$

Divide each term in $- 5 (- 3 - 4 x) = 75$ by $- 5$ and simplify.

Divide each term in $- 5 (- 3 - 4 x) = 75$ by $- 5$ .

$\frac{- 5 (- 3 - 4 x)}{- 5} = \frac{75}{- 5}$

Simplify the left side.

Cancel the common factor of $- 5$ .

Cancel the common factor.

$\frac{- 5 (- 3 - 4 x)}{- 5} = \frac{75}{- 5}$

Divide $- 3 - 4 x$ by $1$ .

$- 3 - 4 x = \frac{75}{- 5}$

Simplify the right side.

Divide $75$ by $- 5$ .

$- 3 - 4 x = - 15$

Move all terms not containing $x$ to the right side of the equation.

Add $3$ to both sides of the equation.

$- 4 x = - 15 + 3$

Add $- 15$ and $3$ .

$- 4 x = - 12$

Divide each term in $- 4 x = - 12$ by $- 4$ and simplify.

Divide each term in $- 4 x = - 12$ by $- 4$ .

$\frac{- 4 x}{- 4} = \frac{- 12}{- 4}$

Simplify the left side.

Cancel the common factor of $- 4$ .

Cancel the common factor.

$\frac{- 4 x}{- 4} = \frac{- 12}{- 4}$

Divide $x$ by $1$ .

$x = \frac{- 12}{- 4}$

Simplify the right side.

Divide $- 12$ by $- 4$ .

$x = 3$