Solve for x log base 5 of x=-1

$\log_{5} (x) = - 1$

Rewrite $\log_{5} (x) = - 1$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b \neq 1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

$5^{- 1} = x$

Solve for $x$ .

Rewrite the equation as $x = 5^{- 1}$ .

$x = 5^{- 1}$

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$x = \frac{1}{5}$

The result can be shown in multiple forms.

Exact Form:

$x = \frac{1}{5}$

Decimal Form:

$x = 0.2$

Solve for x log base 5 of x=-1

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