Solve for x log base 8 of x=2/3

$\log_{8} (x) = \frac{2}{3}$

Step 1

Rewrite $\log_{8} (x) = \frac{2}{3}$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b \neq 1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

$8^{\frac{2}{3}} = x$

Step 2

Solve for $x$ .

Rewrite the equation as $x = 8^{\frac{2}{3}}$ .

$x = 8^{\frac{2}{3}}$

Simplify $8^{\frac{2}{3}}$ .

Simplify the expression.

Rewrite $8$ as $2^{3}$ .

$x = {(2^{3})}^{\frac{2}{3}}$

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x = 2^{3 (\frac{2}{3})}$

Cancel the common factor of $3$ .

Cancel the common factor.

$x = 2^{3 (\frac{2}{3})}$

Rewrite the expression.

$x = 2^{2}$

Raise $2$ to the power of $2$ .

$x = 4$

Solve for x log base 8 of x=2/3

Related Questions

Support LCMGCF.com by disabling your adblocker.