Solve for x log base a of a^2=x

$\log_{a} (a^{2}) = x$

Rewrite the equation as $x = \log_{a} (a^{2})$ .

$x = \log_{a} (a^{2})$

Simplify $\log_{a} (a^{2})$ .

Use logarithm rules to move $2$ out of the exponent.

$x = 2 \log_{a} (a)$

Logarithm base $a$ of $a$ is $1$ .

$x = 2 \cdot 1$

Multiply $2$ by $1$ .

$x = 2$